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Coordination Compounds

Question
CBSEENCH12007309
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Explain Co(NH3)63+ is an inner orbital complex whereas Ni(NH3)62+ is an outer orbital complex.

Solution

[Co(NH3)6]3+

[Ni(NH3)6]2+

Electronic configuration of cobalt = d6

Electronic configuration of Nickel = d8

In this compound oxidation state of cobalt is +3

In this compound oxidation state is +2

NH3 is  a strong field ligand therefore it causes the pairing. Hence, Ni can undergo d2sp3 hybridization. Therefore, it is an inner orbital complex.

If NH3 causes the pairing, then only one 3d orbital is empty. Thus, it cannot undergo d 2sp3 hybridization. Therefore, it undergoes sp3d 2 hybridization. Hence, it forms an outer orbital complex.




Some More Questions From Coordination Compounds Chapter

Explain on the basis of valence bond theory that [Ni(CN)4]2–  ion with square planar is diamagnetic and the [NiCl4]2– ion with tetrahedral geometry is paramagnetic.

Predict the number of unpaired electrons in the square planar [Pt(CN)4,]2– ion.

The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacynoion contains only one unpaired electron. Explain using crystal field theory.

Calculate the overall complex dissociation equilibrium constant for the Cu(NH3)42+ion, given β4 for this complex is 2.1 x 1013.

Identify the ligands from the following coordination compounds:
(a)    [Co(en)2Cl(NO2)2]
(b)    K[Co(CN)(CO2)(NO)]
(c)    K3[Al(OH)6]
(d)    [Co(H2O)2(NH3)4](OH)3

Write IUPAC name of the following complexes:
(a)    [Fe(H2O)6]SO4
(b)    [Cu(en)2(NO3)2

Give IUPAC name of the following complexes:
(i) Na2[Fe(CN)5(NO)],       (ii) K2[Zn(CN)4]

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