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Coordination Compounds

Question

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Give evidence that [Co(NH₃)₅Cl]SO₄ and [Co(NH₃)₅SO₄]Cl are ionisation isomers.

Solution

The ionisation isomers dissolve in water to yield different ions and thus react differently to various reagents:

[Co ({NH}_{3})_{5} C l] {SO}_{4} + {Ba}^{2 +} \to {BaSO}_{4} (s) ↓

[Co ({NH}_{3})_{5} {SO}_{4}] C l + {Ba}^{2 +} \to No reaction [Co ({NH}_{3})_{5} C l] {SO}_{4} + {Ag}^{+} \to No reaction [Co ({NH}_{3})_{5} {SO}_{4}] C l + {Ag}^{+} \to Ag C l (s)

Some More Questions From Coordination Compounds Chapter

Write the formula for the following coordination compound:
Iron(III) hexacyanidoferrate(II)

Write the IUPAC names of the following coordination compounds:
(i) [Co(NH₃)₆]Cl₃(ii) [Co(NH₃)₅Cl]Cl₂
(iii) K₃[Fe(CN)₆]
(iv) K₃[Fe(C₂O₄)_3]
(v) K₂[PdCl4]
(vi) [Pt(NH₃)₂Cl(NH₂CH₃)]Cl.

Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:
(i) K[Cr(H₂O)₂(C₂O₄)₂], (ii) [Co(en)₃Cl₃,
(iii) [Co(NH₃)₅(NO₂)]|NO₃]₂, (iv) [Pt(NH₃)(H₂O)Cl₂]

Explain on the basis of valence bond theory that [Ni(CN)₄]^2– ion with square planar is diamagnetic and the [NiCl₄]^2– ion with tetrahedral geometry is paramagnetic.

Predict the number of unpaired electrons in the square planar [Pt(CN)₄,]^2– ion.

The hexaquo manganese(II) ion contains five unpaired electrons, while the hexacynoion contains only one unpaired electron. Explain using crystal field theory.

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