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State Boyle's Law?
Boyle’s Law : Temperature remaining constant the volume of a given mass of dry gas is inversely proportional to its pressure.
=T=Constant
Calculate the degrees of freedom for monoatomic, diatomic and triatomic gas?
The degrees of freedom of the system is given by:- f=3 N-K
where f = degrees of freedom
N = Number of Particles in the system.
K = Independent relation among the particles.
what do you mean by mean free path and write the formula?
In kinetic theory the mean free path of a particle, such as a molecule, is the average distance the particle travels between collisions with other moving particles. The formula still holds for a particle with a high velocity relative to the velocities of an ensemble of identical particles with random locations.
A charged particle moves through a magnetic field perpendicular to its direction. Then
the momentum changes but the kinetic energy is constant
both momentum and kinetic energy of the particle are not constant
both, momentum and kinetic energy of the particle are constant
kinetic energy changes but the momentum is constant
A.
the momentum changes but the kinetic energy is constant
The mass of a hydrogen molecule is 3.32 x 10-27 kg. If 1023 hydrogen molecules strike, per second, a fixed wall of area 2cm2 at an angle of 45° to the normal, and rebound elastically with a speed of 103 m/s, then the pressure on the wall is nearly:
4.70 x 102 N/m2
2.35 x 103 N /m2
4.70 x 103 N/m2
2.35 x 102 N /m2
B.
2.35 x 103 N /m2
Change in momentum
The kinetic energies of a planet in an elliptical orbit about the Sun, at positions A, B and C are KA, KB and KC, respectively. AC is the major axis and SB is perpendicular to AC at the position of the Sun S as shown in the figure. Then
KA < KB < KC
KA > KB > KC
KB > KA > KC
KB < KA < KC
B.
KA > KB > KC
Speed of the planet will be maximum when its distance from the sun is minimum as mvr = constant
Point A is perihelion and C is aphelion.
Clearly, VA> VB>VC
So, KA>KB>KC
A solid sphere is in rolling motion. In rolling motion, a body possesses translational kinetic energy (Kt) as well as rotational kinetic energy (Kr) simultaneously. The ratio Kt: (Kt+ Kr) for the sphere is
7:10
5:7
2:5
10:7
B.
5:7
In rolling motion, rotational kinetic energy.
A graph between pressure P (along with the y-axis) and absolute temperature, T (along with the x-axis) for equal moles of two gases have been drawn. Given that the volume of the second gas is more than the volume of first gas. Which of the following statement is correct?
Slope of gas 1 is less than gas 2
Slope og gas 1 is more than gas 2
Both have some slopes
None of the above
B.
Slope og gas 1 is more than gas 2
According to the ideal gas equation,
pV = nRT .... (i)
P/T represents the slope of the graph. As the number of moles is the same for the two gases.
A sphere of diameter 0.2 m and mass 2 kg is rolling on an inclined plane with velocity u = 0.5 mls. The kinetic energy of the sphere is
0.1 J
0.3 J
0.5 J
0.42 J
D.
0.42 J
The kinetic energy of sphere while rolling on an inclined plane is given by
EK =Tanslational kinetic energy + Rotational kinetic energy
Pressure of an ideal gas is increased by keeping temperature constant. What is the effect on kinetic energy of molecules?
increase
Decrease
No change
Can't be determined
C.
No change
Kinetic energy of ideal gas depends only on its temperature. Hence, it remains constant whether its pressure is increased on decreased.
Pressure of an ideal gas is increased by keeping temperature constant. What is effect on kinetic energy of molecules?
Increase
Decrease
No change
Cannot be determined
C.
No change
The kinetic energy of an ideal gas depends only on its temperature. Hence, it remains constant whether its pressure is increased or decreased.
For a gas = 0.67. This gas is made up of molecules which are
monoatomic
polyatomic
mixture of diatomic and polyatomic molecules
diatomic
A.
monoatomic
The molecule of a monoatomic gas has three translational degrees of freedom. Thus the average energy of a molecule at temperature T is ( 3/2 ) kBT.
Given:-
So,
= 1.5 R
=
This value corresponds to monoatomic
A horizontal tube of length l closed at both ends, contains an ideal gas of molecular weight M. The tube is rotated at a constant angular velocity ω about a vertical axis passing through an end. Assuming the temperature to be uniform and constant. If p1 and p2 denote the pressure at free and the fixed end respectively, then choose the correct relation
A.
Consider the diagram
Consider the elementary part of thickness dx at a distance x from the axis of rotation, then force on this part
Adp = (dm)ω2 x ......(i)
where, dm = mass of element
ω = angular velocity
Now, from ideal gas equation
pV = nRT
R - Avagadro constant
V = Volume
n = Number of moles of gas
pA dx =
⇒ dm = ......(ii)
From Eqs. (i) and (ii)
Adp =
0(minimum) to l (maximum) is the limit
⇒
⇒ ln
⇒
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Two rigid boxes containing different ideal gases are placed on table. Box A contains one mole of nitrogen at temperature T0 , while box B contains 1 mole of helium at temperature 7/3 T0. The boxes are then put into thermal contact with each other and heat flows between them until the gases reach a common final temperature (ignore the heat capacity of boxes) then the final temperature of gases, Tf in terms of T0 is
C.
We know the Ideal gas law
PV = nRT
Given:- T1 = T0 and T2 =
T =
∴ Tf =
=
Tf =
The temperature of the cold junction of thermocouple is 0°C and the temperature of hot junction is To C. The emf is E = 16T - 0.04T2 µV. The inversion temperature Tf is
300o C
200o C
500o C
400o C
D.
400o C
The thermocouple is an electrical device consisting of two dissimilar electrical conductors forming electrical junctions at different temperatures.
Given emf E = 16 T - 0.04 T2 μV
At inversion temperature, E = 0
⇒ 16 T - 0.04T2 = 0
⇒ 0.04 T2 = 16T
⇒ Tf =
⇒ Tf = 400o C
The temperature of a gas is raised from 27° C to 927° C. The root mean square speed
gets halved
gets doubled
is times the earlier value
remains the same
B.
gets doubled
Given:-
T1 = 27oC = 300 K
T2 = 927oC = 1200 K
According to Kinetic theory of ideal gas
vrms =
vrms =
Where m - mass of the molecules
- mean of squared speed
⇒ vrms =
∴
( vrms )2 = 2 ( vrms )1
Two different isotherms representing the relationship between pressure p and volume V at a given temperature of the same ideal gas are shown for masses m1 and m2 , then
Nothing can be predicted
m1 < m2
m1 = m2
m1 > m2
B.
m1 < m2
pV = nRT
=
For m1
p = ....(i)
For m2
p = .....(ii)
From Eqs. (i) and (ii), we get
Thus, V ∝ m
V2 > V1
m2 > m1
1 mole of H2 gas is contained in a box of volume V = 1.00 m3 at T = 300 K. The gas is heated to a temperature of T = 3000 K and the gas gets converted to a gas of hydrogen atoms. The final pressure would be (considering all gases to be ideal)
same as the pressure initially
2 times the pressure initially
10 times the pressure initially
20 times the pressure initially
D.
20 times the pressure initially
According to Ideal gas equation
PV = nRT
⇒
Here T2 = 3000 K, T1 = 300 K
Since H2 splits into hydrogen atoms, therefore volume become half
i.e V2 = V1
∴
∴ = 20
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