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Kinetic Theory

Question

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A particle is moving in a circular path of radius a under the action of an attractive potential U = -k/2r². its total energy is:

$- \frac{3}{2} \frac{k}{a^{2}}$

$\frac{- k}{4 a^{2}}$

$\frac{k}{2 a^{2}}$

zero

Solution

zero

Given,

$U = - \frac{k}{2 r^{2}} \Rightarrow F_{r} = - \frac{d U}{d r} = - \frac{k}{r^{3}} S i n c e t h e p a r t i c l e m o v e s i n a c i r c u l a r p a t h o f r a d i u s' a' \frac{m v^{2}}{a} = \frac{k}{a^{3}} \Rightarrow m v^{2} = \frac{k}{a^{2}} . . . . (1) K i n e t i c e n e r g y = \frac{1}{2} m v^{2} = \frac{k}{2 a^{2}} T o t a l e n e r g y = - \frac{k}{2 a^{2}} + \frac{k}{2 a^{2}} = 0$

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Kinetic Theory

A particle is moving in a circular path of radius a under the action of an attractive potential U = -k/2r². its total energy is:

$- \frac{3}{2} \frac{k}{a^{2}}$

$\frac{- k}{4 a^{2}}$

$\frac{k}{2 a^{2}}$

zero

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Pressure of an ideal gas is increased by keeping temperature constant. What is the effect on kinetic energy of molecules?

Pressure of an ideal gas is increased by keeping temperature constant. What is effect on kinetic energy of molecules?

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Kinetic Theory

A particle is moving in a circular path of radius a under the action of an attractive potential U = -k/2r2. its total energy is: -32ka2 -k4a2 k2a2 zero

Some More Questions From Kinetic Theory Chapter

Pressure of an ideal gas is increased by keeping temperature constant. What is the effect on kinetic energy of molecules?

Pressure of an ideal gas is increased by keeping temperature constant. What is effect on kinetic energy of molecules?

Mock Test Series

NCERT Sample Papers

Entrance Exams Preparation

A particle is moving in a circular path of radius a under the action of an attractive potential U = -k/2r². its total energy is:

$- \frac{3}{2} \frac{k}{a^{2}}$

$\frac{- k}{4 a^{2}}$

$\frac{k}{2 a^{2}}$

zero