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NCERT Solutions for Class 12 Help.html Physics Part Ii Chapter 10 Wave Optics

Wave Optics Here is the CBSE Help.html Chapter 10 for Class 12 students. Summary and detailed explanation of the lesson, including the definitions of difficult words. All of the exercises and questions and answers from the lesson's back end have been completed. NCERT Solutions for Class 12 Help.html Wave Optics Chapter 10 NCERT Solutions for Class 12 Help.html Wave Optics Chapter 10 The following is a summary in Hindi and English for the academic year 2025-26. You can save these solutions to your computer or use the Class 12 Help.html.

Question 1
CBSEENPH12038172

A small candle, 2.5 cm in size is placed at 27 cm in front of a concave mirror of radius of curvature 36 cm. At what distance from the mirror should a screen be placed in order to obtain a sharp image? Describe the nature and size of the image. If the candle is moved closer to the mirror, how would the screen have to be moved?

Solution
Given, 

Object size = 2.5 cm

Object distance, u = -27 cmRadius of curvature, R = 36 cmFocal length,  f =R2 = -362 = -18 cmImage distance, 1v = 1f-1u = -118-1-27                         1v = 127-118 =- 154i.e.,                          v = -54 cm

The negative sign indicates that the image is formed in front of the mirror. Thus, the screen should be placed at a distance of 54 cm in front of the mirror on the same side as that of the object. 

Now,
Magnification, m = IO = -vu

              I2.5 =-54-27         I = - 5 cm 

As size of image is (–)ve. So image is inverted and real. 

When the candle is moved closer to mirror, the screen would have to be moved farther and farther. However, when the candle is closer than 18 cm from the mirror, the image would be virtual and therefore cannot be collected on the screen.


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