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Thermodynamics
Derive an expression for the work done during Isothermal expansion
Work done during isothermal expansion of 1 mole of ideal gas
W = ∫ dW
v2
W = ∫ Pd V - - - - ( I )
v1
For 1 mole of gas
PV = RT
P = RT / V
Putting value of P in eqn ( I ).,
v2
W = ∫ RT / V dV
v1
v2
W = RT ∫ 1 / V dV
v1
v2
W= RT [ log e V]
v1
W = RT [ log e V2 - log e V1 ]
W = 2.303 RT log 10 V2 / V1
For constant temperature,
W = 2.303 RT log 10 P2 / P1
Sponsor Area
When a system is taken from state i to state f along the path iaf, it is found that Q = 50 cal and W = 20 cal. Along the path’ ibf Q = 36 cal. W along the path ibf is
The work of 146 kJ is performed in order to compress one kilo mole of gas adiabatically and in this process the temperature of the gas increases by 7° C. The gas is
(R = 8.3 J mol−1 K−1 )
Which of the following is incorrect regarding the first law of thermodynamics?
A system goes from A to B via two processes I and II as shown in the figure. If ∆U1 and ∆U2 are the changes in internal energies in the processes I and II respectively, the
Which of the following statements is correct for any thermodynamic system?
Sponsor Area
Sponsor Area