Atoms And Molecules

Question

A stone is released from the top of a tower of height 19.6 m. Calculate its final velocity.

Answer

Given, a stone is released from the top of a tower. 
Initial velocity, u = 0 m/s
Acceleration due to gravity, g = -9.8 m/s2 
Distance covered by the ball during the course of it's motion = 19.6 m 
Now, usign the equation of motion, 
                   v2 - u2 = 2ags
We have,
     v2 - 02 = 2 * (-9.8) * (-19.6) 
i.e.,  v2 - 02 = (19.6)2 
i.e.,   v = - 19.6 m/s
The negative sign indicates that the velocity is acting in the downward direction

Sponsor Area