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Atoms And Molecules

Question

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Calculate the number of aluminium ions present in 0.56 gm of aluminium oxide.

Solution

1 mole of aluminium oxide, Al₂O₃= 2 X 27+3 X 16 = 102 u = 102 gmSo, 102 gm has Al₂O₃ has = 6.023 X 10²³ Al₂O₃ molecules   0.56 gm Al₂O₃ has 6.023 X1023 X 0.56
                                               102

         = 3.01 X 10²¹ Al₂O₃ molecules

1 molecules of Al₂O₃ gives =2Al³⁺ ions

Hence 0.56 gm Al₂O₃ gives = 2 X 3.01 X 10²¹ Al³⁺ ions

= 6.023 X 10²¹ aluminium ions

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