Real Numbers
Use Euclid’s division algorithm to find the HFC of 867 and 255
Given integers are 867 and 255.
Clearly 867 > 255
Therefore, by applying Euclid’s division lemma to 867 and 255, we get
II. Since the remainder 102 ≠ 0, we apply division lemma to get,
III. We consider the new divisor 102 and new remainder 51 and apply division lemma to get,
The remainder at this step is zero. So, the divisor at this stage or the remainder at the previous stage i.e., 51 is the HCF of 867 and 255.
Sponsor Area
Express each number as a product of its prime factors: (ii) 156
Express each number as a product of its prime factors: (ii) 156 (iii) 3825 (iv) 5005 (v) 7429
Express each number as a product of its prime factors: (iv) 5005
Express each number as a product of its prime factors: (v) 7429
Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. (i) 26 and 91
Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. (ii) 510 and 92
Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. (iii) 336 and 54
Find the LCM and HCF of the following integers by applying the prime factorisation method. (i) 12, 15 and 21
Find the LCM and HCF of the following integers by applying the prime factorisation method. (ii) 17, 23 and 29
Find the LCM and HCF of the following integers by applying the prime factorisation method. (iii) 8, 9 and 25
Sponsor Area
Sponsor Area