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Real Numbers

Question

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Find the LCM and HCF of the following integers by applying the prime factorisation method. (i) 12, 15 and 21

Solution

(i) 12, 15 and 21

Now, 12 = 2 × 2 × 3= 2² × 3,

15 = 3 × 5, 21 = 3 × 7

Here, 3 is the smallest common prime factor.

∴ H.C.F. (12, 15, 21) = 3

And 2², 3¹, 5¹ and 7¹ are the greatest powers of prime factors.

∴ L.C.M. (12, 15,21)= 2² × 3¹ × 5¹ × 7¹ =420.

Some More Questions From Real Numbers Chapter

Express each number as a product of its prime factors: (ii) 156 (iii) 3825 (iv) 5005 (v) 7429

Express each number as a product of its prime factors: (iv) 5005

Express each number as a product of its prime factors: (v) 7429

Find the LCM and HCF of the following pairs of integers and verify that LCM × HCF = product of the two numbers. (i) 26 and 91

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Find the LCM and HCF of the following integers by applying the prime factorisation method. (i) 12, 15 and 21

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