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Coordination Compounds
Question
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The geometry and magnetic behaviour of the complex [Ni(CO)4] are

  • Square planar geometry and diamagnetic

  • Tetrahedral geometry and diamagnetic

  • Tetrahedral geometry and paramagnetic

  • Square planar geometry and paramagnetic

Answer

B.

Tetrahedral geometry and diamagnetic

Ni(28) : [Ar]3d8 4s2
∵CO is a strong field ligand, so unpaired electrons get paired. Hence, the configuration would be.

For, four ‘CO’-ligands hybridisation would be sp3 and thus the complex would be diamagnetic and of tetrahedral geometry.

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Some More Questions From Coordination Compounds Chapter

Write the formula for the following coordination compound:
Dichloridobis(ethane-1, 2-diamine)platinum(lV) nitrate.

Write the formula for the following coordination compound:
Iron(III) hexacyanidoferrate(II)

Write the IUPAC names of the following coordination compounds:
(i) [Co(NH3)6]Cl3
(ii) [Co(NH3)5Cl]Cl2
(iii) K3[Fe(CN)6]
(iv) K3[Fe(C2O4)3]
(v) K2[PdCl4]
(vi) [Pt(NH3)2Cl(NH2CH3)]Cl.

Indicate the type of isomerism exhibited by the following complexes and draw structures for these isomers:
(i)    K[Cr(H2O)2(C2O4)2],                      (ii) [Co(en)3Cl3,
(iii) [Co(NH3)5(NO2)]|NO3]2,                 (iv) [Pt(NH3)(H2O)Cl2]

Explain on the basis of valence bond theory that [Ni(CN)4]2–  ion with square planar is diamagnetic and the [NiCl4]2– ion with tetrahedral geometry is paramagnetic.

Predict the number of unpaired electrons in the square planar [Pt(CN)4,]2– ion.