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The p-Block Elements
Question
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Oxidation states of P in H4P2O5, H4P2O6, H4P2O7, are respectively

  • +3, +5, +4

  • +5, +3, +4

  • +5, +4,+3

  • +3, +4, +5

Answer

D.

+3, +4, +5

Oxidation state of H is +1 and that of O is -2
Let the oxidation state of P in the given compound x.
In  H4P2O5,
(+1) x 4 +2 X x + (-2) x 5 = 0
4 + 2x -10 = 0
2x = 6
x = 3
In  H4P2O6, 
(+1) X 4 + 2 X x + (-2) x6 = 0
4 x + 2x-12 = 0
2x = 8
x =4
In  H4P2O7,
(+1) x 4 x 2 X x + (-2) x 7 = 0
4 + 2x -14 = 0
2x = 10 
x = +5
Thus oxidation states of P in  H4P2O5, H4P2O6, H4P2O7, are +3, +4 and +5.

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Some More Questions From The p-Block Elements Chapter

Why are pentahalides more covalent than trihalides?

Why is BiH3 the strongest reducing agent amongst all the hydrides of Group 15 elements?

Why is N2 less reactive at room temperature?

Mention the conditions required to maximise the yield of ammonia.

What is the covalency of nitrogen in N2O5?

Bond angle in PH4+ is higher than that in PH3. Why?

Write a balanced equation for the hydrolytic reactions PCl5 in heavy water.