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Electrochemistry
Question
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Molar conductivities (Λom) at infinite dilution of NaCl, HCl and CH3COONa are 126.4, 425.9 and 91.0 S Cm2 mol-1 respectively. Λom for CH3COOH will be

  • 425.5 S cm2 mol-1

  • 180.5 S cm2 mol-1

  • 290.8 S cm2 mol-1

  • 390.5 S cm2 mol-1

Answer

D.

390.5 S cm2 mol-1

CH3COONa +HCl → NaCl + CH3COOH
91 + 425.9 = 126.4 + x
x= 516.9 -126.4
= 390.5 S cm2 mol-1

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