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Electrochemistry
Write the chemistry of recharging the lead storage battery, highlighting all the materials that are involved during recharging.
Answer:
A secondary cell after use can be recharged by passing current through it in the opposite direction so that it can be used again.
Recharging: During charging process, hydrogen ions moves to cathode and sulphate ions to anode and the following reactions take place
At cathode:
PbSO4 + H2 → Pb + H2SO4
At anode:
PbSO4 + SO4 + 2H2O → PbO2 + 2H2SO4
Thus, during charging active materials namely Pb cut the cathode and PbO2 at the anode are formed. Sulphuric acid is formed and water is iconsumed. Due to this, the specific gravity of sulphuric acid increases and emf of the cell goes up to 2.2 volt.
Some More Questions From Electrochemistry Chapter
Why does the conductivity of a solution decrease with dilution?
Suggest a way to determine the Λ°m value of water.
The molar conductivity of 0.025 mol L–1 methanoic acid is 46.1 S cm2 mol–1. Calculate its degree of dissociation and dissociation constant. Give λ°(H+) = 349.6 S cm2 mol–1 and λ° (HCOO– ) = 54.6 s cm2 mol–1.
If the current of 0.5 ampere flows through a metallic wire for 2 hours, then how many electrons flow through the wire?
Suggest a list of metals that are extracted electrolytically.
Consider the reaction: Cr2O72– + 14H+ + 6e- → 2Cr3+ + 8H2O
What is the quantity of electricity in coulombs needed to reduce 1 mol of Cr2O72-?
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