Give reasons:
i) SO₂ is reducing while TeO₂ is an oxidizing agent.
ii) Nitrogen does not form pentahalide.
iii) ICl is more reactive than I₂

i) Sulphur dioxide is reducing agent because sulphur has d-orbital so it can easily expand its oxidation state +4 to +6 and thus behave as reducing agent.
in the case of TeO₂, Te is a heavier element and due to inert pair effect, the Te does expand its oxidation state +4 to +6.

ii) The electronic state of Nitrogen is 1s² 2s² 2p³. Nitrogen does not have d orbital and due to the absence of d -orbital it does not form pentahalide.

iii) ICl is more reactive than I₂ because I-Cl bond in ICl is weaker than I-I bond in I₂.