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Electrochemistry
Question
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Calculate the molar conductance at infinite dilution of ethanoic acid from the following data:
Λ°m (HCl) = 425.9 s cm2 mol–1
Λ°m (CH3COONa) = 91.0s cm2 mol–1
Λ°m (NaCl) = 126.4 s cm2 mol–1

Answer

Λ°m (CH3COOH) = λ°H+ + λ°CH3coo–
= Λ°m(HCl) = λ°m (CH3COONa) – λ°NaCl
= 425.9 + 91.0 –126.4
= 390.5 s cm2 mol–1.

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