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Electrochemistry
Question
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The resistance of a conductivity cell containing 0.01 M KCl solution at 298 K is 1500 Ω. What is the cell constant if conductivity of 0.001 M KCl solution at 298 K. is 1.46 x 10–6 s cm–1.

Answer

We ave given that 

R = 1500 Ω
K = 1.46 x 10–4 Ω–1 cm–1

Cell constant = K x R

= 1.46 x 10–4 x 1500 = 0.219

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