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Moving Charges And Magnetism

Question
CBSEENPH12039794

A long straight wire of radius a carries a steady current I. The current is uniformly distributed over its cross-section. The ratio of the magnetic fields B and B' at radial distances straight a over 2 and 2a respectively, from the axis of the wire is,

  • 1 half
  • 1

  • 4

  • 1/4

Solution

B.

1

b) Consider two amperian loops of radius a/2 and 2a as shown in the diagram.

Applying Ampere's circuital law for these loops, we get
contour integral B. d L space equals space mu subscript o space I subscript e n c l o s e d end subscript
For the smaller loop,
rightwards double arrow space straight B space straight x space 2 straight pi straight a over 2 equals straight mu subscript straight o straight x straight I over πa squared xπ space open parentheses straight a over 2 close parentheses squared
space space space space space space space space space space space space space space space space space space space space space equals space straight mu subscript straight o space straight I space straight x space 1 fourth space equals space fraction numerator straight mu subscript straight o space straight I over denominator 4 end fraction
rightwards double arrow straight B subscript straight I space equals space fraction numerator straight mu subscript straight o straight I over denominator 4 πa end fraction
B1 acts at a distance a/2 from the axis of the wire.
Similarly, for bigger amperian loop,
B' x 2 straight pi (2a) = straight mu subscript straight o straight I 
Total current enclosed by amperian loop 2.
rightwards double arrow space straight B apostrophe space equals space fraction numerator straight mu subscript straight o straight I over denominator 4 πa end fraction, at a distance 2a from the axis of the wire.
Therefore,
Ratio of fraction numerator straight B over denominator straight B apostrophe end fraction space equals space fraction numerator mu subscript o I over denominator 4 pi a end fraction x fraction numerator 4 pi a over denominator mu subscript o I end fraction equals 1