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Moving Charges And Magnetism

Question
CBSEENPH12039686
Wired Faculty App

In the circuit, the galvanometer G shows zero deflection. If the batteries A and B have negligible internal resistance, the value of the resistor R will be

  • 200Ω

  • 100Ω

  • 500 Ω

  • 1000 Ω

Solution

B.

100Ω

The potential drop across the resistance R is 2V. Now, no current flows through the galvanometer .and if V1 is the potential drop across the resistor R and V is the total potential then
fraction numerator VR over denominator 500 space plus straight R space end fraction space space equals space straight V subscript 1 fraction numerator 12 space straight R over denominator 500 space plus straight R space end fraction space equals space 2 space equals space 100 space ohm

Some More Questions From Moving Charges And Magnetism Chapter

Two moving coil meters, M1 and M2 have the following particulars:
R1 = 10 Ω   N1 = 30,
A1 = 3.6 x 10–3 m2,  B1 = 0.25 T
R2 = 14 Ω;  N2 = 42,
A2 = 1.8 x 10–3 m2, B2 = 0.50 T
(The spring constants k are identical for the two meters).
Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of M2 and M1.

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