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Moving Charges And Magnetism

Question
CBSEENPH12039592

A current loop ABCD is held fixed on the plane of the paper as shown in the figure. The arcs BC (radius = b) and DA (radius = a) of the loop are joined by two straight wires AB andCD. A steady current I is flowing in the loop. Angle made by AB and CD at the origin O is 30º. Another straight thin wire with steady current I1 flowing out of the plane of the paper is kept at the origin.


Due to the presence of the current I1 at the origin


The magnitude of the magnetic field (2) due to the loop ABCD at the origin (O) is

  • The forces on AB and DC are zero

  • The forces on AD and BC are zero

  • The magnitude of the net force on the loop is given by fraction numerator straight mu subscript straight o II subscript 1 over denominator 4 straight pi end fraction space open square brackets 2 left parenthesis straight b minus straight a right parenthesis space plus space straight pi over 3 left parenthesis straight a plus straight b right parenthesis close square brackets

  • The magnitude of the net force on the loop is given by fraction numerator straight mu subscript 0 space II subscript 1 over denominator 24 space ab end fraction space left parenthesis straight b minus straight a right parenthesis

Solution

B.

The forces on AD and BC are zero

The forces on AD and BC are zero because magnetic field due to a straight wire on AD and BC is parallel to elementary length of the loop.