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Moving Charges And Magnetism

Question
CBSEENPH12039353

Use Biot-Savart law to derive the expression for the magnetic field on the axis of a current carrying circular loop of radius R.

Draw the magnetic field lines due to a circular wire carrying current I.

Solution
Here,
I = current in the loop
R= radius of the loop
X= distance between O and P
dl = conducting element of the loop
According to the Biot-Savart law,
Magnetic field at point P is,
dB space equals space fraction numerator straight mu subscript straight o over denominator 4 straight pi end fraction space fraction numerator straight I space vertical line dl space straight x space straight r vertical line over denominator straight r cubed end fraction

straight r squared space equals space space straight x squared space plus space straight R squared
Since space dl space and space straight r space is space perpendicular comma space

vertical line dl space straight x space straight r vertical line space equals space straight r space dl

Therefore comma

dB space equals space fraction numerator straight mu subscript straight o over denominator 4 straight pi end fraction. space fraction numerator straight I. space dl over denominator left parenthesis straight x squared plus straight R squared right parenthesis end fraction
dB has two components: dBx and dB subscript perpendicular.
dB subscript perpendicular is cancelled out and the x-component remains.
Therefore,
dB subscript straight x space equals space dB space cos space straight theta

cos space straight theta space equals space fraction numerator straight R over denominator left parenthesis straight x squared plus straight R squared right parenthesis to the power of bevelled 1 half end exponent end fraction
therefore space dB subscript straight x space equals space fraction numerator straight mu subscript straight o straight I space dl over denominator 4 straight pi end fraction. space fraction numerator straight R over denominator left parenthesis straight x squared space plus space straight R squared right parenthesis to the power of bevelled 3 over 2 end exponent end fraction
Summation of dl over the loop is given by,
B = straight B subscript straight x straight i with hat on top space equals space fraction numerator straight mu subscript straight o space straight I space straight R squared over denominator 2 space left parenthesis straight x squared plus straight R squared right parenthesis to the power of bevelled 3 over 2 end exponent end fraction space straight i with hat on top
Magnetic field lines due to a circular current carrying i is,