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Moving Charges And Magnetism

Question
CBSEENPH12039215

(a) Draw a labelled diagram of a moving coil galvanometer. Describe briefly its principle and working.

(b) Answer the following:

(i) Why is it necessary to introduce a cylindrical soft iron core inside the coil of a galvanometer?

(ii) Increasing the current sensitivity of a galvanometer may not necessarily increase its voltage sensitivity. Explain, giving reason.

Solution

b) Moving coil galvanometer:
  
Principle: The underlying principle of moving coil galvanometer is that a current carrying coil, placed in a uniform magnetic field, experiences torque.

Consider a rectangular coil for which no. of turns = N

Are of cross-section is A = lb

Intensity of the uniform magnetic field = B

Current through the coil = I

Therefore,

Deflecting torque is given by,

BIL x b = BIA

For N number of turns,

straight tau= NBIA

Restoring torque in the spring = kstraight theta

Therefore, 
        NBIA space equals space kθ

This space implies comma space

straight I thin space equals space open parentheses straight k over NBA close parentheses straight theta

That space is comma space

straight I space proportional to space straight theta  

b) i) The soft iron coil in a galvanometer will make the field radial. Also, it increases the strength of the magnetic field.
ii) Current sensitivity in the galvanometer is given by, straight theta over straight I space equals space fraction numerator N B A over denominator k end fraction
Voltage sensitivity in the galvanometer is given by, 
straight theta over straight V space equals space fraction numerator theta over denominator I R end fraction space equals space open parentheses fraction numerator n B A over denominator k end fraction close parentheses. begin inline style 1 over R end style
The above two equations imply that increasing the current sensitivity may not necessarily increase the voltage sensitivity.