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Moving Charges And Magnetism

Question
CBSEENPH12039297

Two long, straight, parallel conductors carry steady currents, I1 and I2 , separated by a distance . If the currents are flowing in the same direction, show how the magnetic field set up in one produces an attractive force on the other? Obtain the expression for this force. Hence, define one ampere.

Solution
                                       
Magnetic field induction at some point P on wire 2 due to current I1 passing through wire 1 is given by, 
                                       straight B subscript 1 space equals space fraction numerator straight mu subscript straight o space 2 space straight I subscript 1 over denominator 4 space straight pi space straight d end fraction 
Magnetic field is produced by wire 1 and current carrying wire 2 lies in magnetic field B1.
 The unit length of wire 2 will experience a force, given by 
                              F= B1 I2 x 1 = fraction numerator straight mu subscript straight o over denominator 4 straight pi end fraction space fraction numerator 2 space I subscript 1 space I subscript 2 over denominator d end fraction

According to Fleming's left-hand rule, the force on wire 2 acts in the plane of paper perpendicular to wire 2, directed towards wire 1. Similarly, wire 1 also experiences the same force towards wire 2. Thus, both the conducting wires attract each other with the same force F.
One ampere can be defined as the amount of current flowing through two parallel conductors, which are in the same direction or opposite directions, placed at a distance of one metre in free space, and both the wires attract or repel each other with a force of 2 x 10-7 per metre of their lengths.