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Moving Charges And Magnetism

Question
CBSEENPH12039281

(a) State the principle of the working of a moving coil galvanometer, giving its labelled diagram.

(b) “Increasing the current sensitivity of a galvanometer may not necessarily increase its voltage sensitivity.” Justify this statement.

(c) Outline the necessary steps to convert a galvanometer of resistance RG into an ammeter of a given range.

Solution

a) Principle of moving galvanometer: 

A current carrying coil when kept inside a uniform magnetic field, can experience a torque.

When current (I) is passed in the coil, torque acts on the coil given by, 
straight tau space equals space NIAB space sin space straight theta

where q is the angle between the normal to plane of coil and the magnetic field of strength B,

N is the number of turns in a coil.

When the magnetic field is radial, as in the case of cylindrical pole pieces and soft iron core, then in every position of coil the plane of the coil, is parallel to the magnetic field lines, so that

straight theta= 90° and sin 90° =1 

Deflecting Torque is given by, 
straight tau space equals space NIAB

If C is the torsional rigidity of the wire and q is the twist of suspension strip, then restoring torque =C

For equilibrium, deflecting torque = restoring torque,
Error converting from MathML to accessible text. 

That is, deflection of coil is directly proportional to current flowing in the coil.
  
b) 

Clearly, the voltage sensitivity is dependent on current sensitivity and the resistance of the galvanometer. If we increase current sensitivity and resistance G is larger, then it is not certain that voltage sensitivity will be increased. Thus, the increase of current sensitivity does not imply the increase of voltage sensitivity.
c) 
Conversion of galvanometer into ammeter:

Inorder to convert galvanometer into ammeter a shunt resistance i.e., a small resistance in parallel is connected across the coil of galvanometer.

Let G be the resistance of galvanometer and Ig the current required for full scale deflection.

Suppose this galvanometer is to converted into ammeter of range I ampere and the value of shunt required is S.

If, Is is the current in the shunt, then 
space space space space space straight I space equals space straight I subscript straight g space plus space straight I subscript straight S space

rightwards double arrow space straight I subscript straight S space equals space left parenthesis straight I space minus space straight I subscript straight g right parenthesis
Also space potential space difference space across space straight A space and space straight B comma

straight V subscript AB space equals space straight I subscript straight S. straight S space equals space straight I subscript straight g. straight G

Substituting space value space of space straight I subscript straight S space from space left parenthesis straight i right parenthesis comma space we space get
rightwards double arrow space left parenthesis straight I space minus space straight I subscript straight g right parenthesis straight S space equals space space straight I subscript straight g space straight G

rightwards double arrow space space IS space minus space straight I subscript straight g straight S space equals space straight I subscript straight g straight G

rightwards double arrow IS space equals space space straight I subscript straight g space left parenthesis straight S plus straight G right parenthesis

rightwards double arrow space space straight I subscript straight g space equals fraction numerator straight S over denominator straight S space plus space straight G end fraction straight I

straight i. straight e. comma space shunt space required comma space straight S space equals space fraction numerator GI subscript straight g over denominator straight I space minus space straight I subscript straight g end fraction 

which is the required expression for conversion of galvanometer into ammeter.