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Moving Charges And Magnetism

Question
CBSEENPH12039071

Two identical circular wires P and Q each of radius R and carrying current ‘I’ are kept in perpendicular planes such that they have a common center as shown in the figure. Find the magnitude and direction of the net magnetic field at the common center of the two coils. 

Solution

Coils P and Q each of radius R have a common centre:

BP is directed vertically upwards and BQ is directed horizontally.

Therefore, resultant magnetic field is given by,
straight B subscript straight R straight space equals straight space square root of straight B subscript straight P squared plus straight B subscript straight Q squared end root
We have,
straight B subscript straight P straight space equals straight space straight B subscript straight Q equals fraction numerator straight mu subscript straight o straight I over denominator 2 straight R end fraction

rightwards double arrow                         straight B straight space equals straight space square root of 2 straight B subscript straight P equals square root of 2 fraction numerator straight mu subscript straight o straight I over denominator 2 straight R end fraction
rightwards double arrow                         straight space straight B straight space equals straight space fraction numerator straight mu subscript straight o straight I over denominator square root of 2 straight R end fraction
This is the required of the resultant magnetic field. 

Direction of magnetic field is given by, 
tan straight space straight theta straight space equals straight space straight B subscript straight P over straight B subscript straight Q equals 1
theta equals pi over 4
The resultant magnetic field is directed at angle of 45° with either of the fields.