Question

A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?

Solution

Here,

Length of the wire, l = 3.0 cm = $3 \times 10^{- 2} m$

Current, I = 10 A

Uniform magnetic field, B = 0.27 T

$θ = 90 °$

Magnetic force on the wire, F = ?

Now using the formula,

F = BI l $\sin θ$ = $0.27 \times 10 \times (3 \times 10^{- 2}) \sin 90^{o} = 0.27 \times 10 \times 3 \times 10^{- 2} \times 1 = 8.1 \times 10^{- 2} N$

Some More Questions From Moving Charges And Magnetism Chapter

Two moving coil meters, M₁ and M₂ have the following particulars:
R₁ = 10 Ω N₁ = 30,
A₁ = 3.6 x 10^–3 m², B₁ = 0.25 T
R₂ = 14 Ω; N₂ = 42,
A₂ = 1.8 x 10^–3 m², B₂ = 0.50 T
(The spring constants k are identical for the two meters).
Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of M₂ and M_1.

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Moving Charges And Magnetism

A 3.0 cm wire carrying a current of 10 A is placed inside a solenoid perpendicular to its axis. The magnetic field inside the solenoid is given to be 0.27 T. What is the magnetic force on the wire?

Some More Questions From Moving Charges And Magnetism Chapter

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