The wire shown in figure below carries a current of 60 A. Find the magnetic field B at P.

Solution

Given, current carried by the wire, I= 60 A .

The field at P arises from 3/4th of the circular loop only because P lies on the straight wires themselves.
Thus,

B = \frac{μ_{0}}{4 π} \frac{2 πl}{r} \frac{θ}{360} θ = 270 ° T h e r e f o r e, B = \frac{3 \times 10^{- 7} \times 2 π \times 60}{4 \times 0.02} = 1.4 \times 10^{- 3} T

Some More Questions From Moving Charges And Magnetism Chapter

Two moving coil meters, M₁ and M₂ have the following particulars:
R₁ = 10 Ω N₁ = 30,
A₁ = 3.6 x 10^–3 m², B₁ = 0.25 T
R₂ = 14 Ω; N₂ = 42,
A₂ = 1.8 x 10^–3 m², B₂ = 0.50 T
(The spring constants k are identical for the two meters).
Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of M₂ and M_1.

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Moving Charges And Magnetism

The wire shown in figure below carries a current of 60 A. Find the magnetic field B at P.

Some More Questions From Moving Charges And Magnetism Chapter

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