The force $\vec{F}$ experienced by a particle of charge ‘q’ moving with a velocity ‘v’ in a magnetic field ‘B’ is given by $\vec{F} = q (\vec{v} \times \vec{B}) .$ Which pairs out of these vectors are always at right angles to each other?

Solution

The force acting on the particle is always perpendicular to the velocity of the particle and also, the magnetic field .

i.e.,

\vec{F} ⊥ \vec{v} and \vec{F} ⊥ \vec{B} .

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