Find the magnitude of the force on each segment of the wire shown, if a magnetic field of 0.30 T, is applied parallel to AB and DE take the value of current flowing in the wire, as 1 ampere.

Solution

Given,
Magnetic field applied on segment AB and DE, B = 0.30 T
Current flowing in the wire, I = 1A
Therefore,

Force acting on the wire, F = IBl sin θ
For segment AB and DE, θ = 0
∴ force acting on these segments is zero.

Force on segment BC = IBl sin 90°
= 1 (B) 8 x 10^–2 = 0.08 B tesla.

Force acting on CD segment, F = 1.B.10 x 10^–2.sin 30°
= 0.05B tesla.

Some More Questions From Moving Charges And Magnetism Chapter

Two moving coil meters, M₁ and M₂ have the following particulars:
R₁ = 10 Ω N₁ = 30,
A₁ = 3.6 x 10^–3 m², B₁ = 0.25 T
R₂ = 14 Ω; N₂ = 42,
A₂ = 1.8 x 10^–3 m², B₂ = 0.50 T
(The spring constants k are identical for the two meters).
Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of M₂ and M_1.

Answer the following questions:
A charged particle enters an environment of a strong and non-uniform magnetic field varying from point to point both in magnitude and direction, and comes out of it following a complicated trajectory. Would its final speed equal the initial speed if it suffered no collisions with the environment?

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Moving Charges And Magnetism

Find the magnitude of the force on each segment of the wire shown, if a magnetic field of 0.30 T, is applied parallel to AB and DE take the value of current flowing in the wire, as 1 ampere.

Some More Questions From Moving Charges And Magnetism Chapter

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