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Moving Charges And Magnetism

Question
CBSEENPH12037640
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An electron of 45 eV energy is revolving in a circular path in a magnetic field of intensity 9 x 10–5 Wb m–2. Determine (i) the speed of the electron (ii) radius of the circular path.

Solution
Energy of electron, E= 45 eV

That is,   
                      
 
which, is the required speed of electron. 

ii) Now, since its a circular path the magnetic force is equal to the centripetal force.

Therefore,   
                      

is the required radius of the circular path. 

Some More Questions From Moving Charges And Magnetism Chapter

Two moving coil meters, M1 and M2 have the following particulars:
R1 = 10 Ω   N1 = 30,
A1 = 3.6 x 10–3 m2,  B1 = 0.25 T
R2 = 14 Ω;  N2 = 42,
A2 = 1.8 x 10–3 m2, B2 = 0.50 T
(The spring constants k are identical for the two meters).
Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of M2 and M1.

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