In Question 4.11 obtain the frequency of revolution of the electron in its circular orbit. Does the answer depend on the speed of the electron?

Solution

Given ,
B = 6.5 G= 6.5

\times

10^-4 T
v= 4.8

\times

10⁶ m/s

Frequency of the revolution of a charged particle is given by

ν = \frac{Bq}{2 πm} = \frac{6.5 \times 10^{- 4} \times 1.6 \times 10^{- 19}}{2 \times 3.14 \times 9.1 \times 10^{- 31}} = \frac{10.4 \times 10^{- 23}}{51.148 \times 10^{- 31}} = 0.18198 \times 10^{8} v = 18 \times 10^{6} Hz = 18 MHz

The frequency is independent of the velocity.

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