Magnetic field at point O will be

$\frac{μ_{o} I}{2 R}$ interior

$\frac{μ_{o} I}{2 R}$ exterior

$\frac{μ_{o} I}{2 R} (1 - \frac{l}{π})$ interior

$\frac{μ_{o} I}{2 R} (1 + \frac{I}{π})$ exterior

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Moving Charges And Magnetism

Question

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Magnetic field at point O will be

$\frac{μ_{o} I}{2 R}$ interior

$\frac{μ_{o} I}{2 R}$ exterior

$\frac{μ_{o} I}{2 R} (1 - \frac{l}{π})$ interior

$\frac{μ_{o} I}{2 R} (1 + \frac{I}{π})$ exterior

Solution

A.

$\frac{μ_{o} I}{2 R}$ interior

Magnetic field at the centre of circular loop

B = $\frac{μ_{o} I}{2 R}$ interior

B is the magnetic field

I is the current flowing through loop

Some More Questions From Moving Charges And Magnetism Chapter

Two moving coil meters, M₁ and M₂ have the following particulars:
R₁ = 10 Ω N₁ = 30,
A₁ = 3.6 x 10^–3 m², B₁ = 0.25 T
R₂ = 14 Ω; N₂ = 42,
A₂ = 1.8 x 10^–3 m², B₂ = 0.50 T
(The spring constants k are identical for the two meters).
Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of M₂ and M_1.