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Moving Charges And Magnetism

Question
CBSEENPH12040023
Wired Faculty App

A wire of resistance 12 Ωm-1 is bent to form a complete circle of radius 10 cm. The resistance between its two diametrically opposite point, A and B as shown in the figure, is

  • 0.6 π Ω

  •  3 π Ω

  • 6 π Ω

  • 6 π Ω

Solution

A.

0.6 π Ω


Circumference space of space circle space equals space 2 space xπ space 10 over 100 space equals space fraction numerator 2 straight pi over denominator 10 end fraction space equals space straight pi over 5 Resistance space of space wire space equals space 12 space straight x straight pi over 5 space equals space fraction numerator 12 space straight pi over denominator 5 end fraction Resistance space of space each space section space equals space fraction numerator 12 straight pi over denominator 10 end fraction space straight capital omega therefore comma space Equivalent space resistance equals space fraction numerator fraction numerator 12 space straight pi over denominator 10 end fraction straight x fraction numerator 12 space straight pi over denominator 10 end fraction over denominator fraction numerator 12 space straight pi over denominator 10 end fraction space plus fraction numerator 12 space straight pi over denominator 10 end fraction end fraction space equals space fraction numerator 6 space straight pi over denominator 10 end fraction space equals space 0.6 space πΩ

Some More Questions From Moving Charges And Magnetism Chapter

Two moving coil meters, M1 and M2 have the following particulars:
R1 = 10 Ω   N1 = 30,
A1 = 3.6 x 10–3 m2,  B1 = 0.25 T
R2 = 14 Ω;  N2 = 42,
A2 = 1.8 x 10–3 m2, B2 = 0.50 T
(The spring constants k are identical for the two meters).
Determine the ratio of (a) current sensitivity and (b) voltage sensitivity of M2 and M1.

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