Question
A thermodynamic process is carried out from an original state D to an intermediate state E by the linear process shown in figure
The total work is done by the gas from D to E to F is
100 J
800 J
300 J
250 J
Solution
B.
800 J
Total work done by gas from D to E to F is equal to the area of ΔDEF.
∴ Area of ΔDEF = × DE × EF
Here DF = change in pressure
= 600 200
= 400 N m-2
EF = change in volume
= 7 m3 3 m3
= 4 m3
Area of ΔDEF = × 400 × 4
= 800 J
Thus, the total work done by the gas from D to E to F is 800 J.
