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Mechanical Properties Of Fluids

Question
CBSEENPH11026374

A small spherical drop fall from rest in viscous liquid. Due to friction, heat is produced. The correct relation between the rate of production of heat and the radius of the spherical drop at terminal velocity will be

  • dHdt  1r5

  • dHdt  r4

  • dHdt  1r4

  • dHdt  r5

Solution

D.

dHdt  r5

Viscous force acting on spherical drop

      Fv = 6 πηrv

∴  Terminal velocity v = 29r2 σ - ρη

where, η = coefficient of viscosity of liquid 

  σ = density of material of spherical drop

   ρ = density of liquid

Power imparted by viscous force = Rate of production of heat

     P = dHdt

        = Fv . v

         = 6 πηrv2

          = 6 πηrv . 29 r2 σ - ρ gη2

 ⇒   dHdt ∝ r5