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Thermodynamics

Question
CBSEENPH11026161

An ideal gas heat engine operates in Carnot cycle between 227o C and 127o C. It absorbs 6 × 104 cal of heat at higher temperature. Amount of heat converted to work is

  • 2.4 × 104 cal

  • 6 × 104 cal 

  • 1.2  × 104

  • 4.8  × 10cal

Solution

C.

1.2  × 104

The heat converted to work is the amount of heat that remains after going through the sink.
From the relation

Q1Q2 = T2T1Given :- Q1 = 6 × 104 calT1 = 227+ 273 = 500 KT2 = 127 + 273 = 400 K Q26 × 104 = 400500Q2 = 45 × 6 × 104 cal

Now heat converted to work:-

Q1 - Q2= 6.0 × 104 - 4.8 ×104= 1.2  × 104 cal