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Thermodynamics

Question
CBSEENPH11020842

A sample of 0.1 g of water at 100°C and normal pressure (1.013 × 105 Nm–2) requires 54 cal of heat energy to convert to steam at 100°C. If the volume of the steam produced is 167.1 cc, the change in internal energy of the sample, is

  • 104.3 J

  • 208.7 J

  • 84.5 J

  • 42.2 J

Solution

B.

208.7 J

Applying first law of thermodynamics equation.

Q = U + W54 x 4.18 = U + 1.013 x 105 (167.1 x 10-6 - 0)( W = PV)U = 208.7 J