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Motion In Straight Line

Question
CBSEENPH11020537

A ship A is moving Westwards with a speed of 10 kmh-1 and a ship B 100km  south of A, is moving Northwards with a speed of 10 kmh-1. The time after which the distance between them becomes shortest is

  • 0 h

  • 5 h

  • 5 square root of 2 space straight h
  • 10 square root of 2

Solution

B.

5 h

It is clear from the diagram that the shortest distance between the ship A and B  is PQ.

Here comma space sin space 45 degree space equals space PQ over OQ
rightwards double arrow space PQ space equals space 100 space straight x fraction numerator 1 over denominator square root of 2 end fraction space equals space 50 square root of 2 space straight m
Also comma space straight v subscript AB space equals space square root of straight v subscript straight A superscript 2 plus straight v subscript straight B superscript 2 end root space equals space square root of 10 squared plus 10 squared end root space equals space 10 square root of 2 space km divided by straight h
So comma space time space taken space ofr space to space reach space shortest space path space is space
straight t equals PQ over straight v subscript AB space equals space fraction numerator 50 square root of 2 over denominator 10 square root of 2 end fraction space equals space 5 straight h