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Motion In Straight Line

Question
CBSEENPH11019919

A player throws a ball upwards with an initial speed of 29.4 m s-1.


To what height does the ball rise and after how long does the ball return to the player’s hands ?

(Take g = 9.8 m s-2and neglect air resistance).

Solution
Initial velocity of the ball, u = 29.4 m/s 
At maximum height, the velocity of the ball becomes zero.
Final velocity of the ball, v = 0 

Acceleration, a = – g = – 9.8 m/s2  
Using third equation of motion, 
Height to which the ball rises is given by, 
straight v squared space minus space straight u squared space equals space 2 gs

straight s space equals space fraction numerator left parenthesis straight v squared minus straight u squared right parenthesis over denominator 2 straight g end fraction space

space space equals fraction numerator space left square bracket left parenthesis 0 right parenthesis squared space minus space left parenthesis 29.4 right parenthesis squared right square bracket space over denominator 2 cross times left parenthesis negative 9.8 right parenthesis end fraction space space equals 44.1 space straight m
Also comma space

Time space of space ascent space equals space Time space of space desent space

So comma space total space time space taken space by space the space ball space to space return space to space the space
p layer apostrophe straight s space hand space is comma

straight t space equals space 3 space plus space 3 space equals space 6 space sec