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Motion In Straight Line

Question
CBSEENPH11019909

A woman starts from her home at 9.00 am, walks with a speed of 5 km h–1 on a straight road up to her office 2.5 km away, stays at the office up to 5.00 pm, and returns home by an auto with a speed of 25 km h–1. Choose suitable scales and plot the x-t graph of her motion.

Solution
Speed space of space the space woman space equals space 5 space km divided by hr

Distance space between space her space office space and space home space equals space 2.5 space km space

Time space taken space equals space fraction numerator Distance space over denominator Speed end fraction equals fraction numerator 2.5 over denominator 5 end fraction space equals space 0.5 space straight h space equals space 30 space min space

Given space that space the space woman space covers space the space same space distance space in space the space evening. space

Speed space of space the space auto space equals space 25 space km divided by hr

Time space taken space equals Distance over Speed equals fraction numerator 2.5 over denominator 25 end fraction equals 1 over 10 equals 0.1 space straight h space equals space 6 space min

Distance minus time space graph space for space the space motion space of space woman space is space shown space below. space