Question
Two limbs of hydraulic lift have area of cross-section 5 cm2 and 100 cm2. To lift the weight of 24 kg placed on 5 cm2 cross-section, what force must be applied on the piston of cross-section 100 cm2?
Solution
Given, two hydraulic lifts.
Area of cross-section of first limb = 5 cm2
Area of cross section of second limb = 100 cm2
Weight of the load = 24
Area of cross-section on which the load is kept = 5 cm2
Now, using Pascal's law, we have
Here, a1 = 5 cm2 , F1 = 235 N
a2 = 100 cm2
So, force F2 = , is the force applied on a piston of cross-sectional area 100 cm2.
Area of cross-section of first limb = 5 cm2
Area of cross section of second limb = 100 cm2
Weight of the load = 24
Area of cross-section on which the load is kept = 5 cm2
Now, using Pascal's law, we have
Here, a1 = 5 cm2 , F1 = 235 N
a2 = 100 cm2
So, force F2 = , is the force applied on a piston of cross-sectional area 100 cm2.
