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Motion In Straight Line

Question
CBSEENPH11017858

A remote sensing satellite of the earth revolves in a circular orbit at a height of 250 km above the earth's surface. Calculate the orbital velocity?

Solution

Orbital velocity is given by, 
 straight v subscript straight o space equals space straight R square root of fraction numerator straight g over denominator straight R plus straight h end fraction end root

space space space space equals space 6.38 space straight x space 10 to the power of 6 space square root of fraction numerator 9.8 over denominator 6.38 space straight x space 10 to the power of 6 space plus space 0.250 space straight x space 10 to the power of 6 end fraction end root space

space space space space equals space 7756.6 space straight m divided by straight s