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Motion In Straight Line

Question
CBSEENPH11017849

A satellite orbits the earth at a height of 500 km from its surface. Calculate the P.E of the satellite.

Mass of the satellite is 300 kg,
Mass of the earth = 6 x 1024 kg
Radius of the Earth = 6.4 x 106 m
G = 6.67 x 10-11 N m2 kg-2

Solution

P.E of the satellite is given by, 
Potential space Energy space of space the space satellite comma space straight P. straight E space equals space minus GMm over straight r

space space space space space space space space space space space space space space space space space space space space equals space fraction numerator negative left parenthesis 6.67 space straight x space 10 to the power of negative 11 end exponent right parenthesis space straight x space left parenthesis 6 space straight x 10 to the power of 24 right parenthesis space straight x space 300 over denominator 7 space straight x space 10 to the power of 6 end fraction

space space space space space space space space space space space space space space space space space space space space equals space minus 17.4 space straight x space 10 to the power of 9 space straight J