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Motion In Straight Line

Question
CBSEENPH11017789

A satellite orbits the earth at a height of 500 km from its surface. Compute its:

(a) kinetic energy 

(b) potential energy

(c) total energy.

Mass of the satellite = 300 kg,
Mass of the earth = 60 x 1024kg,
Radius of the earth = 6.4 x 106m
G = 6.67 x 10-11 Nm2/kg2. 

Will your answers alter if the earth shrinks suddenly to half of its present size?

Solution

We have,
Mass of the satellit, m = 300 kg
Mass of the Earth, M= 6.0 x 1024kg
Radius of Earth, R = 6.4 x 106m
Gravitational constant, G = 6.67 x 10-11 Nm2/kg2
(a) Kinetic energy of satellite is,
1 half mv subscript straight o squared space space equals space 1 half straight m open parentheses square root of fraction numerator GM over denominator straight R plus straight h end fraction end root close parentheses squared space

space space space space space space space space space space space space space space space space equals space fraction numerator GMm over denominator 2 left parenthesis straight R plus straight h right parenthesis end fraction
            equals fraction numerator 6.67 cross times 10 to the power of negative 11 end exponent cross times 6.0 cross times 10 to the power of 24 cross times 300 over denominator 2 left parenthesis 6 cross times 10 to the power of 6 plus 0.5 cross times 10 to the power of 6 right parenthesis end fraction
            equals space 8.7 cross times 10 to the power of 9 straight J
(b) Potential energy of satellite is, 
negative fraction numerator G M m over denominator straight R plus straight h end fraction space equals space minus fraction numerator 6.67 cross times 10 to the power of negative 11 end exponent cross times 6.0 cross times 10 to the power of 24 cross times 300 over denominator 6.9 cross times 10 to the power of 6 end fraction straight J 
            space space equals negative 17.4 cross times 10 to the power of 6 straight J 

(c)Total energy of satellite is, 
E = K.E. + P.E.
   = 8.7 x 109 -17.4 x 10
   = -8.7 x 109
(d) If the earth shrinks to half its size without changing its mass, the answers will remain the same.