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Motion In Straight Line

Question
CBSEENPH11017757

A body is projected with a velocity 14 km/s from the surface of the earth. Find the velocity of body at infinity. Escape velocity at the surface of the earth is 11.2 km/s.

Solution

Let v be the velocity of body at infinity.
By using law of conservation of energy, we have
          space space space space 1 half mv squared minus GMm over straight R equals 1 half mv subscript infinity superscript 2 plus 0 
rightwards double arrow      space space space space 1 half mv squared minus 1 half mv subscript straight e superscript 2 equals 1 half mv subscript infinity superscript 2 

rightwards double arrow                            straight v subscript infinity equals square root of straight v squared minus straight v subscript straight e superscript 2 end root
Here, we have
Velocity with which the body is projected,straight v equals 14 space km divided by straight s
Escape velocity, straight v subscript straight e equals 11.2 space km divided by straight s
∴ Velocity of body at infinity, straight v subscript infinity space equals space square root of left parenthesis 14 right parenthesis squared minus left parenthesis 11.2 right parenthesis squared end root space equals space 8.4 space km divided by straight s