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Motion In Straight Line

Question
CBSEENPH11017678

Three point masses each of mass m are placed at the vertices of an equilateral triangle of side l. What is the gravitational potential due to three masses at the centriod of the triangle?

Solution
Let three masses each of mass m be placed at the vertices of an equilateral triangle ABC of side l.
Let O be the centroid of the triangle.
              
The distance of centroid from each vertex is, 
            r = AO = BO = CO = space ell divided by square root of 3 
The gravitational potential at O due to mass m at A is,
            straight V subscript straight A equals negative Gm over straight r equals negative fraction numerator square root of 3 Gm over denominator ell end fraction 
Similarly, 
 
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and       Error converting from MathML to accessible text. 
Therefore total potential due to all the three masses is,
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