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Motion In Straight Line

Question
CBSEENPH11017669

Two masses of 25 kg and 75kg are separated by a distance 20m. Find the gravitational potential at a point at a distance of 5 m from 25kg mass.

Solution

Given,
Mass of first body, m1 = 25 kg
Mass of second body, m2 = 75 kg
r1 = 5 m and r2 = 15 m
           
Let straight V subscript 1 space and space straight V subscript 2 be the gravitational potential due to masses 25 kg and 75 kg respectively. 
Using the formula for gravitational potential,
  straight V subscript 1 equals negative GM subscript 1 over straight r subscript 1 equals fraction numerator 6.66 cross times 10 to the power of negative 11 end exponent cross times 25 over denominator 5 end fraction 
     equals space 3.33 space cross times space 10 to the power of negative 10 end exponent straight J divided by kg            

and
space space space space space space space space straight V subscript 2 equals negative GM subscript 2 over straight r subscript 2 equals fraction numerator 6.66 cross times 10 to the power of negative 11 end exponent cross times 75 over denominator 15 end fraction 
         equals 3.33 cross times 10 to the power of negative 10 end exponent straight J divided by kg 
The total potential at the given point is,
straight V equals straight V subscript 1 plus straight V subscript 2 equals 6.66 cross times 10 to the power of negative 10 end exponent straight J divided by kg, is the gravitational potential at a point at a distance of 5m from the 25 kg mass.