-->

Motion In Straight Line

Question
CBSEENPH11017579

A body weighs 63N on the surface of the earth. What is the gravitational force on it due to the earth at a height equal to half the radius of the earth?

Solution
Acceleration due to gravity at height h from the surface of the earth is,

                straight g subscript straight h equals fraction numerator GM over denominator left parenthesis straight R plus straight h right parenthesis squared end fraction 
                   equals GM over straight R squared 1 over open parentheses 1 plus begin display style straight h over straight R end style close parentheses squared equals straight g over open parentheses 1 plus begin display style straight h over straight R end style close parentheses squared 
where, g is the acceleration due to gravity at the surface of the earth. 
Here, height is equal to the radiuscomma space straight h equals straight R over 2 
∴   straight g subscript straight h equals straight g over open parentheses 1 plus begin display style 1 half end style close parentheses squared equals 4 over 9 straight g 
Gravitational force at given height is, 
            space space straight F equals mg subscript straight h equals 4 over 9 mg 
Weight of the body,  mg equals 63 space straight N 
                                  straight F equals 4 over 9 left parenthesis 63 right parenthesis equals 28 straight N