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Motion In Straight Line

Question
CBSEENPH11017569

The weight of a body at depth d is equal to the weight of the body at height h above the surface of the earth. What is the ratio of h to d, for small value of h and d?

                                 OR

Prove that the distance we have to cover into the earth below its surface is twice the distance we have to cover above the surface of the earth to get the same change in the weight of a body?

Solution
For small value of h, the acceleration due to gravity at height h is, 

               space space space straight g subscript straight h equals straight g open parentheses 1 minus fraction numerator 2 straight h over denominator straight R end fraction close parentheses 
∴            "<pre 
Similarly, at the depth d the weight of body is, 
                  straight W subscript straight d equals mg open parentheses 1 minus straight d over straight R close parentheses 
Since,   space space space space space space space space straight W subscript straight h equals straight W subscript straight d 
i.e.,  
    mg open parentheses 1 minus fraction numerator 2 straight h over denominator straight R end fraction close parentheses space equals space mg open parentheses 1 minus straight d over straight R close parentheses 
∴                          2 straight h equals straight d 
rightwards double arrow                       straight h over straight d equals 1 half