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Motion In Straight Line

Question
CBSEENPH11017467

If the earth were made of lead of relative density 11.3, then what would be the value of g at the surface of earth? Take radius of the earth to be 6.37 x 106m.

Solution
The acceleration due to gravity at the surface of the earth is given by, 
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Here,
straight rho equals 11.3 gm divided by cc space equals space 11300 space kg divided by straight m cubed 
straight R equals 6.37 cross times 10 to the power of 6 straight m
              
straight G equals 6.67 cross times 10 to the power of negative 11 end exponent Nm squared divided by kg squared 
Therefore,
straight g equals fraction numerator 4 cross times straight pi over denominator 3 end fraction cross times 6.67 cross times 10 to the power of negative 11 end exponent cross times 6.37 cross times 10 to the power of 6 cross times 11300 
  equals 20.12 straight m divided by straight s squared